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X^2=1200X
We move all terms to the left:
X^2-(1200X)=0
a = 1; b = -1200; c = 0;
Δ = b2-4ac
Δ = -12002-4·1·0
Δ = 1440000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1440000}=1200$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1200)-1200}{2*1}=\frac{0}{2} =0 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1200)+1200}{2*1}=\frac{2400}{2} =1200 $
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